I dont think so. Your formulas are incorrect.
To find out how many volumes fit in a larger volume, you obviously have to divide volume by volume, not radius. Likewise with areas.
If I take a bucket and fill it with golf balls, is the bucket really full?
On a molecular level, if the bucket is the nanoparticle, then there's no room for other atoms in that nanoparticle, assuming that that the nanoparticle is spherical.Nevertheless, all the volume of the nanoparticle is not used up.
Take a look at this: https://en.wikipedia.org/wiki/Atomic_packing_factor (https://en.wikipedia.org/wiki/Atomic_packing_factor)
BTW, covalent bonding radius is not the correct term, its metallic bonding radius. The values are the same though in this case.
Covalent bonding radius refers to the bond length between unlike atoms, as in sodium chloride for example.
The internal makeup of a particle does not depend on whether it is suspended in water or not.
Crystalline simply means the atoms are arranged in an orderly manner, instead of randomly placed. A dissolved substance cannot be crystalline.
Since silver nanoparticles are not soluble, your last question does not apply to them.
Applying what you learned so far, what is your new estimate for the percentage of surface atoms on a 10nm particle?
Um no. The packing factor says that only 68 to 74% of the volume of the nanoparticle would actually be silver atoms, the rest is empty space. So the nanoparticle will have fewer atoms, not more.
Go back to the bucket of golf balls, and see all the empty space that cannot hold another golf ball.
And if we divide that with the volume of a silver atom, which have a radius of 0.145 nm, equal to an atomic volume of 1.28 nm3, we get 356 to 524 / 1.28 = 278 to 409 atoms in the nanoparticle.Not even close.
@PeterXXL: Although you got the wrong answer so far, I want to tell you that I like your idea of calculating the surface atoms by subtracting the inside volume from the outside. When I first did these calcs, I did it based on the surface area, but the packing ratio may be different for the surface atoms.
Also, since we are comparing volumes, its unnecessary to bother with the 4/3 pi in the calcs.
So we can just cube the ratios of radii, and apply the packing ratio.
For example: A 12 nm particle has a radius of 6 nm, so the amount of atoms which will fit inside is (6/.155)3*.74 which comes out to 42923
Using your method to find the number of surface atoms, we have 42923 - ((6-.155)/.155)3* .74 = 3241
This gives a value of 7.55% for the percentage of surface atoms for a 12nm particle.
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Is green to small of a particle for us to consume?Unknown.
Can that size still be capped effectively with Gelatin?
Thank you Sir. Excellent reference!
Looking at those samples, It appears our "yellow" results are in the 5-7nm range?
The 10nm sample looks like it would dilute down to more of a pinkish color.
The others are not even close.
Is green to small of a particle for us to consume?
Can that size still be capped effectively with Gelatin?
-Sancho
Light green.Do these colors indicate particle size no matter what process was made to achieve those colors?
This picture shows high ppm samples. (100+ ppm)
The color is determined by the size and shape of the metal particle, not the chemicals used to make it .Not sure why that size comes up when you copy and paste from another location but i went back and fixed it.
BTW, whats with the sizeing? Its annoying, like shouting.